Match List-I with List-II. Choose the correct | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $A \rightarrow$ Kolbe-Schmidt reaction: Phenol reacts with $NaOH$ followed by $CO_2$ and $HCl$ to form salicylic acid. Matches with $IV$.$B \right

Vedclass · Accepted Answer

$A-IV, B-III, C-I, D-II$

Vedclass · Answer

(A) $A \rightarrow$ Kolbe-Schmidt reaction: Phenol reacts with $NaOH$ followed by $CO_2$ and $HCl$ to form salicylic acid. Matches with $IV$.$B \rightarrow$ Reimer-Tiemann reaction: Phenol reacts with $CHCl_3$ and $NaOH$ followed by $HCl$ to form salicylaldehyde. Matches with $III$.$C \rightarrow$ Oxidation of phenol: Phenol is oxidized by $Na_2Cr_2O_7$ and $H_2SO_4$ to $p$-benzoquinone. Matches with $I$.$D \rightarrow$ Williamson ether synthesis: Phenol reacts with $NaOH$ to form sodium phenoxide,which then reacts with $CH_3Cl$ to form anisole $(PhOCH_3)$. Matches with $II$.Therefore,the correct matching is $A-IV, B-III, C-I, D-II$.

Match List-$I$ with List-$II$. Choose the correct answer from the options given below:

Similar Questions

Identify the major product of the following reaction:

Number of isomeric compounds with molecular formula $C_9H_{10}O$ which $(i)$ do not dissolve in $NaOH$ $(ii)$ do not dissolve in $HCl$ $(iii)$ do not give orange precipitate with $2,4-DNP$ $(iv)$ on hydrogenation give identical compound with molecular formula $C_9H_{12}O$ is $...........$

The number of isomeric ethers with molecular formula $C_4H_{10}O$ is:

State the various applications of alcohols,phenols,and ethers in day-to-day life.

Give equations of the following reactions:
$(i)$ Oxidation of propan$-1-$ol with alkaline $KMnO_4$ solution.
$(ii)$ Bromine in $CS_2$ with phenol.
$(iii)$ Dilute $HNO_3$ with phenol.
$(iv)$ Treating phenol with chloroform in presence of aqueous $NaOH$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module